DESCRIPTION OF SCAN DIAGRAM:
Now let's consider the longest time for an output to actually turn on. Let's assume that when a switch turns on we need to turn on a load connected to the plc output.
The diagram below shows the longest delay (worst case because the input is not seen until scan 2) for the output to turn on after the input has turned on.
The maximum delay is thus 2 scan cycles - 1 input delay time.
I don't understand the "worst case because the input is not seen until scan 2" Isn't the input shown activated in scan (1)?
Now let's consider the longest time for an output to actually turn on. Let's assume that when a switch turns on we need to turn on a load connected to the plc output.
The diagram below shows the longest delay (worst case because the input is not seen until scan 2) for the output to turn on after the input has turned on.
The maximum delay is thus 2 scan cycles - 1 input delay time.
I don't understand the "worst case because the input is not seen until scan 2" Isn't the input shown activated in scan (1)?