"TB" in S5 STL?

Johnny T

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• Jan 3, 2007

• #1

Hi and Happy New Year to you all,

I'm converting some software from S5 to S7 and have come across the following code:

C DB120
TB D 3.0
JC =M002
... etc

I don't know what the equivalent of TB is in S7.. I don't even know what the command TB is doing? Has anyone any ideas of what the equivalent S7 code would be to this?

Many thanks for any light you can shed on this.

Cheers

JT ;-)

 

L D[AR2P#0.0]

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L

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• Jan 3, 2007

• #2

TB is test bit and it sets the RLO to the value of the bit.

 

Johnny T

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• Jan 3, 2007

• #3

So would the equivalent in S7 be the following:

A DB120.DBX3.0
JC =M002

???

Thanks

JT

 

L D[AR2P#0.0]

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• Jan 3, 2007

• #4

Yes, provided the A is a 'first check', and also note that

D3.0 == DBX7.0

 

Johnny T

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• Jan 3, 2007

• #5

Why is D3.0 == DBX7.0 ?

I assume you mean that D3.0 is referring to word 6 in S7?

If so would it not be D3.0 == D6.0 ?

Thanks for your patience ;-)

 

L D[AR2P#0.0]

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• Jan 3, 2007

• #6

For reference, the conversions from Step 5 to Step 7 are as follows:

DL n == DBB 2n
DR n == DBB 2n+1
DW n == DBW 2n
DD n == DBD 2n
d n.0..7 == DBX 2n+1.0..7
d n.8..15 == DBX 2n.0..7

 

Last edited: Jan 3, 2007

Johnny T

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• Jan 3, 2007

• #7

Ahhh... I see...


So.. for it to be DBX 6.0 it would be D 3.8 ...

That's cleared a lot of things up.

You're help is very much appreciated.

Cheers

;-)