STL Advice
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L D[AR2P#0.0]
Lifetime Supporting Member
I'm being picky here, but you could swap the order of the loads
to
to save the TAK - but you may be using this fact in the remainder of the code that we can't see.
Also the JC HIGH could be JU HIGH as the RLO will always be true if program flow arrives at this point. The JC implies that there is a decision being made when in fact it has already been made earlier.
Code:
L #Length
L 0.0
==R
Code:
L 0.0
L #Length
==Rto save the TAK - but you may be using this fact in the remainder of the code that we can't see.
Also the JC HIGH could be JU HIGH as the RLO will always be true if program flow arrives at this point. The JC implies that there is a decision being made when in fact it has already been made earlier.
What a difference from the usual 'traffic lights' homework questions.
When someone posts "Quick. I need help with my assignment. Give me the answer." the common response is "Well, show us what you've done so far and we'll help assess it."
But here we have someone who opens up his code straightaway and asks for advice, not on writing it, but on improving it. And they get a prompt relevant response and seem delighted with the answer.
If only they were all like this!
regards
Ken
When someone posts "Quick. I need help with my assignment. Give me the answer." the common response is "Well, show us what you've done so far and we'll help assess it."
But here we have someone who opens up his code straightaway and asks for advice, not on writing it, but on improving it. And they get a prompt relevant response and seem delighted with the answer.
If only they were all like this!
regards
Ken
S7Guy
Member
Combo, I would look at NW1 and see if it is necessary to write constants to the same addresses every time. Usually if my program needs constants, I write to them once during start-up rather than doing it every scan.
Also, another minor point, you could also initialize your CHARs using something other than the byte data type. For instance:
L 'COID'
T DBD 0
It sometimes makes the code a little easier to read.
Yes, I agree. Combo is one of my favorite posters.
Also, another minor point, you could also initialize your CHARs using something other than the byte data type. For instance:
L 'COID'
T DBD 0
It sometimes makes the code a little easier to read.
Ken M said:
Yes, I agree. Combo is one of my favorite posters.
..;
L 'C'
T DB100.DBB 0
L 'O'
T DB100.DBB 1
L 'I'
T DB100.DBB 2
L 'D'
T DB100.DBB 3
L 'K'
T DB100.DBB 4
L 'E'
T DB100.DBB 5
L '$R'
T DB100.DBB 6
L '$L'
T DB100.DBB 7
I wrote it like this tnx to your suggestion:
L 'COID'
T DB100.DBD 0
L 'KE'
T DB100.DBW 4
L '$R'
T DB100.DBB 6
L '$L'
T DB100.DBB 7
L 'C'
T DB100.DBB 0
L 'O'
T DB100.DBB 1
L 'I'
T DB100.DBB 2
L 'D'
T DB100.DBB 3
L 'K'
T DB100.DBB 4
L 'E'
T DB100.DBB 5
L '$R'
T DB100.DBB 6
L '$L'
T DB100.DBB 7
I wrote it like this tnx to your suggestion:
L 'COID'
T DB100.DBD 0
L 'KE'
T DB100.DBW 4
L '$R'
T DB100.DBB 6
L '$L'
T DB100.DBB 7
jacekd
Member
Combo said:
I don't have a CPU at hand to check it for sure, but this also should work:
L 'KE$R$L'
T DB100.DBW4
PeterW
Member
Don't understand why you changed from
OPN DB100
L 'C'
T DBB0
to
T DB100.DBB0
unless the DB is symbolised and the comment is on the DBB is important.
The newer way means that you attempt to open DB100 every time, this uses up scan time, even though the block is already open.
OPN DB100
L 'C'
T DBB0
to
T DB100.DBB0
unless the DB is symbolised and the comment is on the DBB is important.
The newer way means that you attempt to open DB100 every time, this uses up scan time, even though the block is already open.
Hi
http://download.yousendit.com/03EAF95437796354
You can download my project on this link above...
Maybe u can check where it could be written a bit better, I would be thankful, allways open to learn
Thanks in forward
http://download.yousendit.com/03EAF95437796354
You can download my project on this link above...
Maybe u can check where it could be written a bit better, I would be thankful, allways open to learn
Thanks in forward
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