Honeywell S7810M1003 wit Prosoft MVI69MCM

Hi,
Has anyone ever brought a Honeywell S7810m1003 modbus module into a Compactlogix with a prosoft MVI69MCM?

I've read Modbus RTU status data from an S7800 module (not sure if it's a 7810 or not) with SCADA over RS-485.

confused on bringing the fault codes in. Honeywell says they will appear on register, example (the fault code register is 40001 and fault code is 76) what would the register look like with fault code 76?
any help would be appreciated
Thank you

For a fault code 76, which table 17 says is an "accessory fault" (document 65-0249-07, S7810M Modbus Module), register 40001 decimal, (address 0000hex) will hold the 16 bit, unsigned integer 76 decimal.

The next sequential address, 0001hex (register 40002) will hold the 'string code', an unsigned 16 bit integer, in this case 11 decimal. **

Table 17 gives the string code values associated for each fault code.

Table 16 gives the text string displayed by the 7800 for that string code. *

The text string associated with code 11 is ACCESSORY FAULT

The text string itself is not available via Modbus RTU, only the numerical string code representing the text string *is available.

Fault code 76 decimal = 4C hex
The full 16 bit word in register 40001 would be 004C hex.

Some additional information - the S7810M is the old Modbus module without a display. The old S7800A displays didn't have Modbus capabilities. Then new S7800A displays (made in the last few years) can communicate via Modbus on their own.

I see it thank you very much guys, I just have to change the hex to binary in the ladder logic.

Hi danw
did you ever use table 22 on the s7810m Honeywell (burner control state bits)?

Table 22 in which document?

this table 22?

yes that is the table. Table 22 is register 40013 when it is polled it will be copied in the integer files (16 bit integer) so i take it my true bit will be in reference with table 22? This is my first Prosoft job and minimal Modbus experience.
Thank you for your responses

You are correct. 40013 holds the burner control's state bits as a 16 bit unsigned integer.

As the 7800 burner control cycles through its successive states, the value in 40013 will change accordingly. If there's a lockout, both the alarm bit (13) and the lockout bit (15) are set to 1.

Note that not all 7800's can do all states. For instance, not all 7800's can do valve proving or post purge.

Ok Thank you I think it is finally coming together.