Hello men
Using RSLogix 5000 Software
I am having a problem trying to figure out how to properly program the speed of a motor using a VFD with the conditions of discrete outputs. I know I know very easy stuff to you all but I am having problems.
For example:
I have a VFD controling a feed belt. This VFD controls how much sand is on the conveyor. The sand dumps into four different silos via a distributor with four solenoid gate valves controlling which silo we want sand to fall into. Easy enough.
If all four silos are >90% capacity, the feed belt motor can run at max speed (60HZ). If 1 of the 4 silos is <90% capacity, the solenoid gate valve closes for that particular silo and the VFD needs to decrease the speed to (55HZ) which results in less material on the belt so the distributor can handle the amount of material falling into it without the extra gate valve open.
If 2 of 4 silos are <90% capacity...the same thing but it slows down a little more (50HZ) to accomidate the for only two OPEN gate valves.
If 3 of 4 silos <90% capacity...(45HZ)
If 4 of 4 silos <90% capacity...(OHZ) (I got this part...easy)
And lets say...
If 3 of 4 silos "were" <90% full but one of the three was emptied during the process, the feed motor can bump up back up to (50HZ) and so on...
Can anyone at least give me some ideas. I do not expect anyone to write it for me but I just need to some advice on how to figure this thing out. I have tried a few different test programs but no cigar.
Thanks for the help!!!
Kandy
Using RSLogix 5000 Software
I am having a problem trying to figure out how to properly program the speed of a motor using a VFD with the conditions of discrete outputs. I know I know very easy stuff to you all but I am having problems.
For example:
I have a VFD controling a feed belt. This VFD controls how much sand is on the conveyor. The sand dumps into four different silos via a distributor with four solenoid gate valves controlling which silo we want sand to fall into. Easy enough.
If all four silos are >90% capacity, the feed belt motor can run at max speed (60HZ). If 1 of the 4 silos is <90% capacity, the solenoid gate valve closes for that particular silo and the VFD needs to decrease the speed to (55HZ) which results in less material on the belt so the distributor can handle the amount of material falling into it without the extra gate valve open.
If 2 of 4 silos are <90% capacity...the same thing but it slows down a little more (50HZ) to accomidate the for only two OPEN gate valves.
If 3 of 4 silos <90% capacity...(45HZ)
If 4 of 4 silos <90% capacity...(OHZ) (I got this part...easy)
And lets say...
If 3 of 4 silos "were" <90% full but one of the three was emptied during the process, the feed motor can bump up back up to (50HZ) and so on...
Can anyone at least give me some ideas. I do not expect anyone to write it for me but I just need to some advice on how to figure this thing out. I have tried a few different test programs but no cigar.
Thanks for the help!!!
Kandy