Thanks for helping, i have thought of that as well. Looks like my brain's not working well..Thanks a bunch
When you are working with a load of any description you need to understand what you are doing.
I was considering giving you a good ribbing for your question, but, in fareness other people will read this.
Firstly - PLC contacts are normally rated for a resistive load (2A)
AC Loads are not purely resistive so can not normally be directly driven by PLC contacts.
Secondly - A Load listed in wattage can easily be calculated to Current using I = W / V
And Last But Not Least - Frequency of operation
Number of times that a contact operates in a given time.
With a high current load - this will damage contacts very quickly.
As a result - most people are in favor of using additional relays - cheaper to replace and can be correctly sized.
I believe (sorry to you OP) that if you have to ask you are doing the wrong Job and need a lot more training.