s5 . analog input - out put

;Why shift the analog input three times right?
segmen1:

NAME: A-IN_FL
DECL: AIN IW
DECL: TYP DKF
DECL: DOUT QD
DECL: OK QBI
DECL: HIGH DKG
DECL: LOW DKG

segment 2::
L KH 0000
T FW 200
L =AIN
T FW 208
SRW 3 : Why use this command
T FW 202
AN F 208.7
JC =M001
L KH E000
OW
T FW 202
L KH FFFF
T FW 200
M001: L FD 200
FDG
T FD 210

segment 3 ::

L KG 2457.6
L FD 210
<G
= F 250.0

L KG 2048
>G
JC =M001

L KG 307.2
L FD 210
>G
= F 250.0

L KG 409.6
<G
JC =M001

R F 250.0
JU =M002

M001: T FD 210
M002: LWD =HIGH
LWD =LOW
-G
T FD 214
L KG 1638.4
L FD 214
/G
T FD 220

L FD 210
L KG 409.6
-G
T FD 230

AN F 250.0
A T 2
= =OK
L FD 230
L FD 220
/G
LWD =LOW
+G
T =DOUT
BE

No way of knowing ...
But, it's the same as dividing by 8 (divide by 2, 3 times)

In the analog input word, S5 format, the bits 0,1 and 2 is not a part of the value.
They are status indicators, such as as overflow, underflow etc.
It's described in the manual (that I don't have here).

Kalle

link to screen shot of manual:

http://www.plctalk.net/qanda/showpost.php?p=448375&postcount=2

Thanks buddy.
I found out what happened