PLC DL05 with encoder signals wiring

ALIMARY15

Member
Join Date
Jul 2011
Location
italy
Posts
75
Good evening,
I am working on a project where i am using a plc DL05 with an encoder to control an axis position.

My encoder signals A and B, i connected them to the input X0 and X1 of the plc because i am planning to use the HSIO MODE 40 for the quadrature encoder as it states into the plc data-sheet.

I have read that this plc doesn't support signals below the 12 V while instead my signals from the encoder are in TTL logic that means 0-5 V.
As anyone of you ever encountered this problem??how you did solve it??

In my case, to make the signal level fine for the plc i have used a IC circuit called ULN2803. This component i connect one pin to the 5 v and the other one to the 12 V power by a pull-up resistor and to the plc as in the scheme showed attached. When from the right pin side there is a signal, the opposite side pin shows zero and viceversa. So in my case when there is 5v to the other side there will be 0v and if i wanna calculate the Pull-up value that will be Rpul= (12V-0v)/max current into plc.

THe component works just fine and it shows to me the quadrature encoder signals between 12V and 0. Now my question is how can i make the plc be aware of the inputs?
It may seem stupid but i am in need in calculating the pull up resistor value in order to make a certain value of current to arrive to the Xo and X1 inputs.
I don't know what is the current value to make the plc read my signals? I have tried to use a current of around 3mA and calculate the pull up value with this current but the plc doesn't seem to read the inputs.

Thanks a lot

Maria

Schermata 2011-09-15 a 18.10.50.png
 
Bernie have you been down that road before? it sound like you may have been there.

I know the math works out as well.
 
600 ohms provides 5 ma into the input impedance as listed for the module. Of course you can try anything you want but 600 ohms is the result of the calculation. Two 1.2 K in parallel would also work.
 

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