how split double integer into two integers

Hi
I have an application need send some position data to Mitsubishi A800 drive via Modbus rtu. I have double integer value in plc. There are two integers to hold that data in drive side. Each integer value range is 0-9999. I need split the double integer into two integers. Let's say if the double integer value is 123456 i need one integer hold 12 and another hold 3456. i can't figure out how to do it. The plc is fx5u.
Please help me out. thanks.

If that is really what you want to do (sounds wrong, but..)
Integer Divide 123456 by 10000, that gives the 12.
Multiply the 12 by 10000, and subtract that from the original number, that gives the 3456.

IF on the other hand, you actually need to SPLIT the double into two integers with the same binary representation, mask off the value by 0xFFFF0000 shift right (for little endians) 16 bits for the high word, and mask off by 0x0000FFFF for the low word.

rdrast said:

If that is really what you want to do (sounds wrong, but..)
Integer Divide 123456 by 10000, that gives the 12.
Multiply the 12 by 10000, and subtract that from the original number, that gives the 3456.

Click to expand...

That is how we humans understand numbers on 10-base, on PLC integer is 0-65565 or -32768..32767 (depending if integer is unsigned or signed) and splitting with 10000 gives wrong result for drive
Time to shift numbers or calculate differently

Thanks. i check the drive manual again. from what i understand rdrast is right. just divide by 10000 i can get what i want. i also attach the page from manual.