Analog Output follow up

Boxer,

My comment wasn't so much to you as much as to those of us that jumped in with answers to the wrong problem.
 
Download the manual for both the PLC and the option card. THEY ARE FREE!!!

PLC Manual
http://web2.automationdirect.com/static/manuals/d006userm/d006userm.html

Option Cards
http://web2.automationdirect.com/static/manuals/d0optionsm/d0optionsm.html

I'd have to say, and I'm sure most would agree, they are the easiest to understand documentation from any manufacturer.

No one minds helping you understand PLCs. But you would save a lot of time by reading the manuals and asking questions about what you don't understand, as apposed to asking a question and waiting for a reply.

But to answer your question (direct from the manual)–

LD K402 The value is 0402 but shows up as just 402.
Loads a constant that specifies the number of channels to scan and the
data format. The upper byte selects the input data format (i.e. 0=BCD,
8=Binary) and the number of input channels (set to 4). The lower byte
selects the output data format (i.e. 0=BCD, 8=Binary) and the number
of output channels (set to 2).

OUT V710
Special V-memory location, V710, assigned to the option slot
contains the data format and the number of channels to scan.

LDA O2000
This loads an octal value for the first V-memory location that will be used
to store the incoming data. For example, the O2000 entered here would
designate the following addresses:
Ch1 – V2000, Ch2 – V2001, Ch3 – V2002, Ch4 – V2003

OUT V711
The octal address (O2000) is stored here. V711 is assigned to the
option slot and acts as a pointer, which means the CPU will use the
octal value in this location to determine exactly where to store the
incoming data.

LDA O2010
This loads an octal value for the first V-memory location that will be used
to store the output data. For example, the O2010 entered here would
designate the following addresses:
Ch1 – V2010, Ch2 – V2011

OUT V712
The octal address (O2010) is stored here. V712 is assigned to the
option slot and acts as a pointer, which means the CPU will use the
octal value in this location to determine exactly where to get the output
data.
 
Thank you for the input, and I have read the manuals many times. Honestly untill I do one with hands on experience it is all greek in my mind. Now that I reached the end of my program, it seems alot clearer. Guess My mind works in odd ways. I will keep hammering at this untill it all works.

Been trying to get my work to send me to school, but no luck yet, but the only class offered close was Las Vegas, they may have looked at it as more pleasure than learning.
 

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