Someone just had to ask.

[Peter Nachtwey]

Does doubling the pressure double the speed of a hydraulic cylinder provided all other things stay the same? It is safe to say the answer is no because Q=Kv*sqrt(ΔP) where Q is the flow and Kv is the valve flow constant. It is easy to see the flow will be proportional to the square root of the pressure drop but there is more because flow doesn't move things. Force does. Newtwon didn't include flow in his laws of motion.
I love saying that because it ruffles the feathers of the hydraulic guys.

So the velocity will not double when the pressure is doubled. For extra credit and a lot of brownie points, what will the velocity be in the extend direction and in the retract direction. This is something you must solve symbolically.

Steve Bailey figured out the formula years ago and he doesn't even do hydraulic systems. I just saw that Steve was on-line and I know he could spoil the fun like Mildrone and I spoiled Alaric's fun.

Anyway, turn about is fair play.

I would post this at the hydraulic forum but they would never figure this out as they still think flow makes it go. When in reality flow just equalizes pressure.

I heard the info on patchn was gone. That is probably just as well as there was too much noise to filter through to get to the data.

This should keep a few people busy for a few PLC scans.