Do you mean you want to convert this to ladder?
If yes, and you want to do a literal-as-possible translation, then these are all going to have to be Set/Reset (Latch/Unlatch; OTL/OTU) or equivalent, because if qxOut is 0 then the value of zwOut.0 will not be changed.
Is there a third END_IF just out of frame? Because if it's an ELSE instead then there is not enough information here.
I you want to use a single OTE to assign the value to zwOut.0 instead of several OTL/OTUs, then the rungs and branches feeding to that OTE might be near-incomprehensible, so I suggest putting the ST code in the comment.
Is this a homework problem?