Analog I/o Modules

PERSPOLIS · Jan 4, 2003

Hi Experts
In reference to Allen Bradley publication 1746-6.4 January 1996 (SLC 500 Analog I/O Modules) section 4.7 Table 4.d can anybody explain what does 13.67 bits mean .
Many Thanks

Eric Nelson · Jan 4, 2003

I haven't a clue!...

If anyone wants to tackle this one, here's the table Persopolis is referring to:
[attachment]
beerchug

-Eric

PERSPOLIS · Jan 4, 2003

ANALOG MODULE

HI ERIC

you have made it much easier for others to review the inserted page.
Much appreciated

Gerry · Jan 4, 2003

a bit of mathermatical trivia

The geek who wrote the manual must have been having some fun.

just as the range 0-16384 spans 16384 = 2¹⁴
the range 3277-16384 spans 13107 = 2^13.67

actually windows calculator says 2^13.678

Eric Nelson · Jan 5, 2003

So, does this means that the remaining 0.322 of that bit is available for use elsewhere in the program?...

beerchug

-Eric

Gerry · Jan 5, 2003

So, does this means that the remaining 0.322 of that bit is available for use elsewhere in the program?

Oh yes, absolutely!
...using the set of Heisenberg uncertainty instructions coming in a future release...not certain which one.

Allen Nelson · Jan 5, 2003

So, does this means that the remaining 0.322 of that bit is available for use elsewhere in the program?...

No, of course not. The column say "Number of Significant Bits". Therefore that 0.322 bit must be insignificant.

Tom Jenkins · Jan 5, 2003

Actually, the remaining 0.322 bits are available, but Rockwell charges a special bit access fee for it and you need the key disk. This only applies on the Micrologix 1200 Rev 1.1.02.05 or later, and the SLC 5/05.2.3 Rev A.13F (hex).

Analog I/o Modules

PERSPOLIS

Member

Eric Nelson

Lifetime Supporting Member + Moderator

PERSPOLIS

Member

Gerry

Member

Eric Nelson

Lifetime Supporting Member + Moderator

Gerry

Member

Allen Nelson

Member

Tom Jenkins

Lifetime Supporting Member

Similar Topics