I'm having a brain-glitch in trying to display the liquid contents of a silo in kg.
There is a 0-1 bar sensor at the base of the silo. The silo has a conical base. The product has a specific gravity of 1.2.
I've used my tried and trusted function block for the silo volume in litres and added a stage at the beginning and end to correct for the SG of the product. If the silo was a plain vertical cylinder I'd just multiply the final result by the SG to give me kg but as there's a conical base I figured that for a SG other than 1 the sensed height of the product would be incorrect which would affect the calculation for the conical stage and the cone/cylinder interface dimension.
So, I've compensated for the SG at the beginning by using "input level*(1/SG)", then done the volume calc for the whole silo and then I've multiplied the resulting volume (in litres) by the SG to give kg. And it comes out wrong. (Of course, you all say).
Please share your knowledge with someone who's thought long and hard (although apparently not enough) but is still unable to see the wood for the trees. Thank you.
There is a 0-1 bar sensor at the base of the silo. The silo has a conical base. The product has a specific gravity of 1.2.
I've used my tried and trusted function block for the silo volume in litres and added a stage at the beginning and end to correct for the SG of the product. If the silo was a plain vertical cylinder I'd just multiply the final result by the SG to give me kg but as there's a conical base I figured that for a SG other than 1 the sensed height of the product would be incorrect which would affect the calculation for the conical stage and the cone/cylinder interface dimension.
So, I've compensated for the SG at the beginning by using "input level*(1/SG)", then done the volume calc for the whole silo and then I've multiplied the resulting volume (in litres) by the SG to give kg. And it comes out wrong. (Of course, you all say).
Please share your knowledge with someone who's thought long and hard (although apparently not enough) but is still unable to see the wood for the trees. Thank you.