5TI jmp instruction to SLC500

ctmak

Member
Join Date
Aug 2007
Location
Hong Kong
Posts
5
I am trying to convert 5TI program to AB SLC500. But I am not sure the how does jmp instruction work. I try to convert as below. Am I right?

Old rung

condition
0 ----| |-----------------JMP 2----
1 ----| |-----------------( )-----
2 ----| |-----------------( )-----
3 ----| |-----------------( )-----


New rung

condition
0 ----| |-----------------JMP:1----
1 ----| |-----------------( )-----
2 ----| |-----------------( )-----
3 ----[lbl:2]----| |------( )-----
 
No, your example should read

Newer rung

condition
0 ----| |-----------------JMP:1----
1 ----| |-----------------( )-----
2 ----| |-----------------( )-----
3 ----[lbl:1]----| |------( )-----

You need to always reference the same LBL with the JMP label assigned.

This input instruction is the target of JMP instructions having the same
label number. You must program this instruction as the first instruction
of a rung. This instruction has no control bits.
You can program multiple jumps to the same label by assigning the
same label number to multiple JMP instructions. However, label
numbers must be unique.
 

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