Greg7683
Member
Whats it mean when I NO Switch is False does that mean it's at a deadened or something im trying to understand between true and false.
Your question as phrased is hard to understand. A switch that is wired correctly across its NO terminals is understood to be open when in its non-actuated state. Open means there is no current flow across its contacts. There are no conditions other than open and closed.
I don't know what "deadened" means in this context. Do you mean the past tense of the verb "deaden" as in "The addition of thermal insulation also deadened the ambient noise"? Do you mean "dead end" as in "This avenue of research is a dead end"? Do you mean "dead-ended" as in "The road dead-ended at the washed-out bridge"?
The one that drops down and backtracks why would that one be false and wouldn't that be a deadened
You are looking at it the wrong way. That one doesn't drop down and backtrack, it's just called a branch and is a way to put input instructions in parallel.
Each rung, has inputs on the left side, and outputs at the far right, the condition of the input instructions will keep the output off or turn it on.
On that top rung, you have three input instructions, say they are from three different pushbuttons:
PB1, the first instruction at the top of the branch
PB2, the one to the right of PB1
PB3, the one at the bottom of the branch
If PB1 is pressed, that instruction at the top of the branch will turn on. THe output will not turn on, because the PB2 instruction is still off. It will also not run on the PB3 instruction on the bottom of the branch (the backtracking, because PB3 is not pressed. That one on the bottom will only turn on when PB3 is pressed.
Now, if PB2 is pressed, that instruction that is not on the branch turns on.
Again, the output will not turn on, even through the instruction right to its left turns on, because there is not a complete path from the far left of the rung to the output.
If PB2 is pressed, and either PB1 or PB3 is pressed, now one of the instructions on the branch is on, and the instruction to the left of the output is on. The output will turn on, because there is a complete path from the left to the right.
IF PB2 is pressed, to turn on the output, it does not matter is PB1 or PB3 is pressed, it only takes one of the branch instructions being on to complete the path to the output.
So if you are just looking at that rung, either of the two branch instructions in parallel can be on, and the instruction that is not on the branch must be on, to turn on the output.
THe branch (parallel) instructions kind of act like an OR.
If the rung just had two instructions, no branches, that acts like an AND.
So for the top rung that you posted the output is on if (PB1 OR PB3) AND PB2) is true.