maxketcham
Lifetime Supporting Member
50 mv = 0.05v
15.000 v
15/.05= 300
binary of 300 is the value i posted above
count the numbet of bits used = 9
total accuracey is 2^9 bits
or
111111111
or 511
or 0~511
(512 bits)
It is not 512 bits as you stated. it is 9 bits for the example you just stated which would be 512 individual steps in the analog to digital output. the actual output would then be 15/512 or .29 volts per step if 15 volts wer the voltage maximum and O is the minimum range