Case A
Case A can work because voltages can be paralleled and if the inputs are high enough resistance, then there is little loss in the signal.
Case B
Case B does not work (and will never work) because 4-20mA is known as a current loop, which like in all electrical circuits, the current must flow all the way through the loop for it to be a current loop. Your wiring attempts to create 3 loops from a single source and the source cannot regulate the current to three loads.
Case C
Case C appears to be a series loop, where there is one loop where the source current passes through three different analog inputs in series.
If wired properly: output (+) to 1st (+), 1st (-) to 2nd (+), 2nd (-) to 3rd (+), 3rd (-) to output (-), it might work, but the probability is low.
The output must be capable of driving the combined input resistances for all three VFDs. The output is spec'd in terms of how much resistance it can drive and the analog inputs have a spec'd input resistance. It's your job to look those numbers up and see if the the source can drive the drive the total load.
And the inputs must be floating or isolated and not grounded. Otherwise grounding issues add or subtract current from the loop and the result is chaos. This happens all the time. Most inputs are not designed to be run in 4-20mA loop series circuits.
There are splitters that take in one 4-20mA and provide two 4-20mA outputs.
Case D
Case D will not work as drawn, but could with modification.
The 500 ohm resistor must be across the source 4-20mA (+) and (-) terminals.
Then the (+) and (-) terminals are run to each of the VFD voltage inputs (like your Case A)
The voltage will be 2-10Vdc for a 4-20mA signal. If you can configure the 4-20mA signal for 0-20ma, then the voltage will be 0-10Vdc. Sometimes, the scaling on the VFD voltage input can be adjusted to 2-10Vdc.