lupodellasleppa
Member
Hello all,
Thanks for the forum which has provided me with a lot of help overtime.
I'm posting my first thread since I can't seem to find an answer to my issue.
I'll quickly explain the situation: I'll be installing a RTD sensor to a GE Fanuc IC200ALG264 analog input module using a 4-20mA converter.
Everything is fine except I can't seem to understand the polarities of the Fanuc inputs.
I'll explain better: the module has an IC200CHS022 for the terminals, 15 terminals total, and the manual is reporting a "number" and a "connection" for each terminal.
Now, the "number" seems to correspond to the visible pin of the terminal. But the positive and negative symbols are represented on the "connection", which I can't seem to wrap my head around what it means.
Here are abstracts from the manual and a photo of the terminals:
https://pasteboard.co/Jgq31Jz.png
https://pasteboard.co/Jgq1xxC.png
https://pasteboard.co/Jgq2LZU.png
Please tell me where to connect positive and negative outputs of the 4-20mA converter.
Thank you.
Thanks for the forum which has provided me with a lot of help overtime.
I'm posting my first thread since I can't seem to find an answer to my issue.
I'll quickly explain the situation: I'll be installing a RTD sensor to a GE Fanuc IC200ALG264 analog input module using a 4-20mA converter.
Everything is fine except I can't seem to understand the polarities of the Fanuc inputs.
I'll explain better: the module has an IC200CHS022 for the terminals, 15 terminals total, and the manual is reporting a "number" and a "connection" for each terminal.
Now, the "number" seems to correspond to the visible pin of the terminal. But the positive and negative symbols are represented on the "connection", which I can't seem to wrap my head around what it means.
Here are abstracts from the manual and a photo of the terminals:
https://pasteboard.co/Jgq31Jz.png
https://pasteboard.co/Jgq1xxC.png
https://pasteboard.co/Jgq2LZU.png
Please tell me where to connect positive and negative outputs of the 4-20mA converter.
Thank you.