interpreting the moeller ps3 plc

[eng.lionel]

can some help me with changing this code to slc500.
000 L I0.1
001 A NI0.0
002 S M0.0
003 = M0.3
004 0
005 0
006 R M0.0
007 R M0.1

also there is something like
084 C0
U = M0.7
D = M0.3
S = I1.3
R =
I W = KW1000
Z =
Q W = Mw10

 

[Goody]

I'm no Moeller expert or for that matter SLC500. But I can read most of that code

But what do you think it says - have a go and show us what you think it means.

 

[Calistodwt]

You can download a programming manual for the pS4 which can also be used for the PS3 from the link below

http://downloads.applied-automation.com/sam/moeller/ps3/index.html

 

[shooter]

can some help me with changing this code to slc500.
000 L I0.1 get input 0.1
001 A NI0.0 and not input0.0
002 S M0.0 set output marker 0.0
003 = M0.3 result to be put in m0.3
004 0 this can be OR but also NOP or does not make sense
005 0
006 R M0.0 reset m0.0
007 R M0.1 reset m0.1

also there is something like
084 C0 this is counter 0
U = M0.7 it counts up when m0.7 is on
D = M0.3 it counts down when m0.3
S = I1.3 it sets word 1000 when i1.3 is on
R = reset is not used
I W = KW1000 when set this is the number
Z = zero is not used
Q W = Mw10

value of counter is put to MW10

 

[Goody]

So even though the original poster has not replied - and this is a teaching forum, you gave him the answer.
Who has been taught anything?

 

[eng.lionel]

@Shooter, thanx a lot, @Goody, lesson taught.

 

[Goody]

Who has been taught anything?

Me then. Stop trying to educate pork.

 

[ddakic.eu]

i have read manual.
in one sequence i have more than one L (load) and as it says in manual, everyone of them goes in register and you get stacked register.

08 L I 14.11
09 A I 10.4
10
11 L I 14.9
12 O I 14.10
13 AN I 10.4
14 O
15 A M 8.1
16 O
17
18 A I 14.14
19 AN I 14.12
20 S 'S2-VAK

My question is: how is that interpreted because of two L's (in ladder for example)?

line 8 and 9 are in series.
line 11 and 12 are in parallel.
but what in between?