Hello,
Does anyone have any idea what is going to happen with a 3phase AC motor if it connected in Wye when on the motor junction box was specified Delta connection?
Actually, this situation just happened. I did that mistake yesterday, today I found that motor burnet out. In my theoretical knowledge it is not gonna happen:
WWYE = V2 /R
WDELTA = 3(V2)/R
Wye connection with the same Voltage supply will drawn 3 times less power then Delta, so current will be 3 times less. In this case the motor has 3500 RPM and loaded by a fan.
For me it should produce low airflow but never burn out. What I am missing?
Thanks for any help, company about to charge me $1500 for that mistake.
Does anyone have any idea what is going to happen with a 3phase AC motor if it connected in Wye when on the motor junction box was specified Delta connection?
Actually, this situation just happened. I did that mistake yesterday, today I found that motor burnet out. In my theoretical knowledge it is not gonna happen:
WWYE = V2 /R
WDELTA = 3(V2)/R
Wye connection with the same Voltage supply will drawn 3 times less power then Delta, so current will be 3 times less. In this case the motor has 3500 RPM and loaded by a fan.
For me it should produce low airflow but never burn out. What I am missing?
Thanks for any help, company about to charge me $1500 for that mistake.