wilkerson29847
Member
Given this code:
L DBD 8
LAR1
L PID(AR1, P#8.0)
T DBD 38
I understand that whatever is in DBD 8 is loaded into AR1 and then 8 is added to it and that addresses the PID which is transferred to DBD 38. My question is, when it says PID(...), what exactly is it looking at? What would I expect to see in DBD 38, if I looked? Would it be a 32 bit binary number, and if so, where is that number coming from?
Thanks,
David
L DBD 8
LAR1
L PID(AR1, P#8.0)
T DBD 38
I understand that whatever is in DBD 8 is loaded into AR1 and then 8 is added to it and that addresses the PID which is transferred to DBD 38. My question is, when it says PID(...), what exactly is it looking at? What would I expect to see in DBD 38, if I looked? Would it be a 32 bit binary number, and if so, where is that number coming from?
Thanks,
David