showshocka
Member
Sorry for the delay guys...still need help... i did get help from this thread http://www.plctalk.net/qanda/showthread.php?p=483747&posted=1#post483747
here are the projects uploaded
here are the projects uploaded
N7:50 comes from N17:1
(Ladder 2, Rung 48)
N17:1 gets set from N20:1(Ladder 2, Rung 45) conditionally based on the state of B3:7/3
And N20:1 comes from a MSG instruction(Ladder 4, Rung 1) from a device labeled the T-car processor.
...or is B3:44/0 a floating bit?
Paul,
I think a Floating Bit must be like an Always-On trouble-shooter bit. It just floats around looking for someplace that needs a "1" to save the day.
Showshocka, I did a search in your program for B3:44, and turned up nothing in the entire program. What are you talking about? Could you have mis-typed and really meant B3:14/0? There is one case of that bit in Ladder File 5, Rung 023. The only AFI instruction that I found is in Ladder File 6, Rung 000.(Ladder 2, Rung 45) I see they're using B3:44/0 as an AFI for some reason....(?) So how can that rung ever be true? or is B3:44/0 a floating bit?
That explains why I did not find the B3:44/0. We need to all get on the same file here, before someone gets mad!Hey Show, the file you uploaded and the file you are working from are different btw.