no...
32-bit instructions write to at least two registers
(even though you see name of first one only).
32-bit multiply and divide for example write to 4 registers.
DINCP D150 in your example writes to both D150 and D151
(that is 32-bit).
following instruction in your code will change D151 again, as well as D152.
if you want another counter triggered by another bit,
pick next pair of registers such as D152 (and it's successor, D153).
It is good idea to stick to even addresses (D0, D2, D4, D6...)
so you can monitor results in the Device Batch and see meaningful values.