Mitsubishi Division question

[Killercal]

Hello all,

I'm doing some offline programming changes and have run into a problem. There is an instruction that looks like this
[/ D303 K12 D303]

Now I know that this is dividing the value in D303 by 12 and putting the answer back in D303. My question is, what would happen if the value of D303 was 8. Would it give you a value of 0 or 1 or fault out the processor?

Thanks,

Scott

 

[cjd1965]

would give the answer as 0

 

[Killercal]

Thanks!