s5 to s7 conversion

axialpg · Jun 2, 2008

hi all,

i am currently in the process of converting an s5 program to s7 and i have come accross a tir command in the s5 in stl.

does anyone know of an equivalent in s7.

im a bit of a noob to this so please go easy

thanks in advance...Mike

L D[AR2P#0.0] · Jun 2, 2008

You need to understand what the TIR instruction is doing in the Step 5 implementation - maybe its moving data around. You can use indirect addressing in Step 7 or the block move sfc.

aikona · Jun 2, 2008

axialpg said:
hi all,

i am currently in the process of converting an s5 program to s7 and i have come accross a tir command in the s5 in stl.

does anyone know of an equivalent in s7.

im a bit of a noob to this so please go easy

thanks in advance...Mike

Hi

'Load indirect register'

There is an equivalent in S7 but you cannot convert it ...this part of the software you will have to find out exactly what it does and rewrite the software in S7.Have a look at the type of CPU ( in S5) because some special functions use LIR en TIR , also some communication software ( which you also have to rewrite)

Eric

axialpg · Jun 2, 2008

i think that is the problem, because i am so new to plcs, i dont know what the tir command does to be able to convert it or write the equivalent in step 7.

i have searched high and low on here and google to no avail

thanks for your response, i will keep looking.

axialpg · Jun 2, 2008

aikona said:
Hi

'Load indirect register'

There is an equivalent in S7 but you cannot convert it ...this part of the software you will have to find out exactly what it does and rewrite the software in S7.Have a look at the type of CPU ( in S5) because some special functions use LIR en TIR , also some communication software ( which you also have to rewrite)

Eric

thanks alot, i read somewhere else that indirect addressing can be a problem with converting to s7.

i now have a starting point...thanks

L D[AR2P#0.0] · Jun 2, 2008

What is the Step 5 CPU model number - you need to refer to the programming manual for that CPU

aikona · Jun 2, 2008

axialpg said:
i think that is the problem, because i am so new to plcs, i dont know what the tir command does to be able to convert it or write the equivalent in step 7.

i have searched high and low on here and google to no avail

thanks for your response, i will keep looking.

Hi

You sure picked the most obscure statements in the whole book

here are some links : forumSiemens and anotherone also try this and search for LIR and TIR

gives use the the few lines of code before and after the lir/tir and then we try to figure it out, also the CPU type

Greetings Eric

PeterW · Jun 2, 2008

aikona said:
Hi

'Load indirect register'

Eric

Is of course LIR

TIR is transfer indirect register

one loads a value into the accumulator from an indirect address pointed to by the contents of one of the accumultors, whilst the other transfers data from an accumulator to an address pointed to by one of the accumulators.

If I remember right, they would look like LIR 1, LIR 2 etc. Long time since I played with these.

axialpg · Jun 2, 2008

thanks all for your help

the cpu im transferring from is a 115U.

aikona: thanks for the links much appreciated

avatar · Mar 30, 2009

S5-95U to S7-300 (Lir/Tir)

Hi

I've problem about converting two instruction in Simatic S5(95U) to Simatic S7-300. What the Similar Instruction in Simatic S7 for converting TIR and LIR instruction in Simatic S5. Like this:

C DB 181
L KH 7E00
T DW 5
L DW 1
SLW 1
L DW 5
+F
LIR 0
T DW 6
L KF +0
T DW 8

What is the equivalent of this part in S7?
Please help me...

Thanks
Avatar

PeterW · Mar 30, 2009

avatar said:
Hi

I've problem about converting two instruction in Simatic S5(95U) to Simatic S7-300. What the Similar Instruction in Simatic S7 for converting TIR and LIR instruction in Simatic S5. Like this:

C DB 181
L KH 7E00
T DW 5
L DW 1
SLW 1
L DW 5
+F
LIR 0
T DW 6
L KF +0
T DW 8

What is the equivalent of this part in S7?
Please help me...

Thanks
Avatar

Code:

C DB 181    //Call DB181
L KH 7E00   //Load offset to DB Address list 
T DW 5      //Store in DW5
L DW 1      //Load DW1
SLW 1       //Double it
L DW 5      //Load DW5 again (unnecessary)
+F          //Add (=(DW1*2)+KH7E00) 
LIR 0       //Load Pointer to DB Start Area (DB number = DW1) value
T DW 6      //Transfer pointer to DW6
L KF +0     
T DW 8      //Transfer 0 into DW8

So obviously this is not the end, maybe this is setting up the start of a block transfer (is there a TNB instruction somewhere) or possibly an indirect offset for single word transfer.

So the word held at absolute memory address KH7E00 is a pointer to the start address of DB0, KH7E02 is the start address of DB1, etc. So whatever number is in DW5 of DB181 is the DB to which this is code is pointing, if DW5 held the value 20, then this bit of code would be setting up a pointer to the start of data of DB20.

To convert this to Step 7, you would need to know -- what happens next?

What you have shown is half the story.

avatar · Mar 31, 2009

It is next instruction :

;
C DB 181 //Call DB181
L KH 7E00 //Load offset to DB Address list >>DB0
T DW 5 //Store in DW5
L DW 1 //Load DW1
SLW 1 //Double it
L DW 5 //Load DW5 again (unnecessary)
+F //Add (=(DW1*2)+KH7E00)
LIR 0 //Load Pointer to DB Start Area (DB number = DW1) value
T DW 6 //Transfer pointer to DW6

L KF +0
T DW 8 //Transfer 0 into DW8... (DB..???)

L DW 4
L KF +0
><F
O(
L DW 1
!=F
)
JC =M001

M001: JU =M004

M004: ***

Thanks for the help

avatar

antonischer · Mar 31, 2009

Hi avatar,

you must find usage of DB118 DW6 somewhere else
cmiiw
anton

avatar · Mar 31, 2009

antonischer said:
Hi avatar,

you must find usage of DB118 DW6 somewhere else
cmiiw
anton

Hi Anton

DB118.DW6 or DB181.DW6...???
if DB181.DW6 :

M003: L DW 8
SLW 1
L KF +4
+F
L DW 6
+F
LIR 0
L KF +0
!=F
JC =M002

L DW 8
L KF +3
+F
T DW 8
JU =M003

Thank's

antonischer · Mar 31, 2009

oops...sorry I mean DB181.DW6
could you upload S5D file here? better if added with INI file

thx

s5 to s7 conversion

axialpg

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