VJN,
As RSDORAN said before, some good example programs are included with the DirectSoft programming package. From the DirectSOft main menu, go to File, Open Project, and then navigate to the "Projects" directory, then to "Samples". I remember that there is one under the DL06 menu that deals with Analog Inputs. That is what you will need to be able to set up. If you see no sample programs, then probably they were not installed by whomever loaded the software program originally. You can reinstall and choose to load the Sample programs.
You will want to set up 6 ladder rungs, one for each of the 6 temperature inputs that your boss mentioned. For each temperature input, you just "scale" the number that is being sent to memory by your analog input. By "scaling" we mean that you take a number that is in one range and convert it to another range. You will want to scale the input (representing a current signal in the range of 4 miliamps to 20 miliamps) to a temperature that matches the range of your thermocouples. Assuming Type J thermocouples (ask the boss if they are Type J), that would be about -346 to 1400 degrees F.
You will need to learn how to set up scaling for Analog Inputs. Below is a link to the Automation Direct Analog Input Manual. You may download it for free, or browse it online.
http://web1.automationdirect.com/static/manuals/d0optionsm/ch3.pdf
The general equation is: Y= mX + b (does that look familiar from your math classes?). m is the Slope, b is the Offset.
For your PLC temperature input, it translates to:
Scaled Value (output) = Slope X Input Value + Offset
Slope (m) = (Scaled Max-Scaled Min)/(Input Max-Input Min)
Offset (b) = Scaled Min - Slope x Input Min)
Some PLC's such as the Allen-Bradley SLC, have a built-in function to do Scaling. Yours doesn't, but no big deal. Just use some math functions. Your DirectSoft Analog Input Module has a Maximum output of 4095 and a Minimum of 0. So your scaling equations become:
Slope = 1400-(-356) divided by (4095-0)= 1756/4095 = 0.4288
Offset = -356 - ( 0.4288 x 0) = -356
Scaled Value (Temperature) = 0.4288 x Input Value -356
Now, all you have to do in each of your 6 rungs is, take the input from the analog input module, multiply it by 0.4288, then subtract 356.
So on each Temperature Input rung, you would do:
LD (load) Vxxx, (where the x's mean a Variable Memory location where you have the analog temperature input. You get to pick where you want it by when you set up the Analog Input Module.)
MUL by 0.4288
SUB 356
OUT Vxxx, where xxx is a V-memory location to record the temperature in degrees F.
I hope this helps! If it sounds like too much, read the above mentioned manual.