Motor 1800 RPM
Encoder 5000 PPR (pulse per revolution)
Speed of shaft after Gearbox = 0.361 RPM
Input card: 800 KHz in A Quad B mode (16 bit accumulator)
I would like to know how to calculate if my system is OK.
I have a motor (1800RPM) on which we wil install an encoder (5000PPR) there is also a gearbox. At the ouput of the gearbox my the speed is 0,361 RPM.
From my calculations it would take
2,77 mins for a 360 turn of system
so 4986 rotation of the motor for 360
so 5000*4986 = 24930000 pulse for complete turn
My accumulator maixmum is 65 536. Am I missing something? And does anybody have a description on how to program such a system. I know I need at least 1 limit switch to do a '0' on the system....
Encoder 5000 PPR (pulse per revolution)
Speed of shaft after Gearbox = 0.361 RPM
Input card: 800 KHz in A Quad B mode (16 bit accumulator)
I would like to know how to calculate if my system is OK.
I have a motor (1800RPM) on which we wil install an encoder (5000PPR) there is also a gearbox. At the ouput of the gearbox my the speed is 0,361 RPM.
From my calculations it would take
2,77 mins for a 360 turn of system
so 4986 rotation of the motor for 360
so 5000*4986 = 24930000 pulse for complete turn
My accumulator maixmum is 65 536. Am I missing something? And does anybody have a description on how to program such a system. I know I need at least 1 limit switch to do a '0' on the system....