mellis
Member
keithkyll said:A dead short is zero ohms. Open is infinity. You need to think backwards when looking at this spec.
Take a 500 Ohm LOAD. Connect another 500 Ohm LOAD in parallel. Now you have a 250 Ohm LOAD. Connect 2 more in parallel, and you will now have a 125 Ohm LOAD.
It's basic Ohms law.
I agree, it's basic Ohm's Law. I think you're just not looking at the circuit from the right point of view.
Basically, what the maximum load specification for a transmitter is saying is: What is the maximum resistance I can shove 20ma through?
Remember, the transmitter controls the current. It can operate with little or no load. That is, it can send a 4-20 ma signal down the wire. It can not operate with an open circuit at all. For a given power supply voltage, there is a maximum load resistance a transmitter can drive. For a 24vdc power supply, the total loop resistance at 20ma will be 1200 Ohms. For a typical transmitter, the load can be up to 600 Ohms. The transmitter makes up the remaining resistance. At 4 ma, the total loop resistance is 6000 Ohms. If the load is a typical 250 Ohm input card, then the transmitter changes from 950 Ohms at 20ma to 5750 Ohms at 4ma.
The example you quoted would apply to a voltage signal. In that case you would have a minimum load resistance. A good example is an audio amp. The output may be specified as 4 Ohm, it means the minimum connected resistance is 4 Ohms. If you connect more speakers in parallel you will lower the connected resistance and exceed the available current.
Also, loads in a 4-20ma loop are in series. So more loads always increases the total connected resistance.
Hope this clarifies things...
edit: Sheesh. Mickey beat me by 5 minutes. Must type faster...
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