Peter Nachtwey
Member
Keith, your units don't work out.This is an extension of V=a2j but you know V and you specify time.
I will let you work out the equation.
Sometimes you have no choice because the speed is low and the distance to stop is small and the maximum deceleration rate is never reached. Both cases should be supported.I personally don't like this method since the acceleration rate isn't bounded. The user needs to make sure in aseparate step that the maximum permissable acceleration rate isn't exceeded.