SLC 500 MOV Instruction

Morning everyone.

I'm using a SLC 5/05 processor for a program I am trying to build. I've posted a couple of rungs here. The code does what it is supposed to do:

1. Move in "0" when the Start Command N10:30/14 is not issued.
2. When N10:30/14 is issued, and we are in Manual N10:30/3 is not set then we move in the value from N24:40. In this case 10.

However my question is, when the Start Command (N10:30/14) AND Auto/Manual Bit are not set (N10:30/3) why does it move in "0" and not the value in n24:40 into N10:68?

I guess my question is, both rungs are "true" and it is moving in "0", it is clearing the register N10:68 and not moving in the 10?
Is there a specific order of operations, or is it easier to move in a constant, or something takes precedence?

I would appreciate any help!

The order of the rungs in the ladder are what take presidence.

When both rungs are true the controller is moving 10 into the register but then it is immediately moving a 0 in over the 10.

If you reverse the order of the rungs then you will always see the value of N24:40 in the register.

Yeah I completely forgot about that... that makes sense.
I appreciate your help.

Thanks!!!