2 INTs to a DINT (controllogix)

I'm stumped, for some reason.

How do I copy 2 ints into a single dint, particularly if byteswap may be involved?

I accomplished it by copying each INT to a temporary INT array in the opposite order then COPied it to my final DINT.

Your post included the keywords: "Copy" and "Swap"

The ordinary COP instruction will move two integers from an INT[x] array into a single DINT when the Length argument is 1. The data moves "bitwise"; it is not converted to a new number like it would be with the MOV instruction.

INT[0] = 0x0123
INT[1] = 0x4567
results in
DINT = 0x01234567

If you need to perform byte swapping, use the SWPB "Swap Bytes" function either before you move the data or after.

Aoppreciate it Ken. I've been out in the field for 2 weeks now, and my online help doesn't seem to be working well.

Like I mentioned, I knew what I wanted to do, just not how to best do it, but my solution, while amateurish, worked.