Sorry don't read #post7 ..
Read this carefully.
thanks you.
LOCUS,
I HAVE GOTTEN YOUR MESSAGE.
PROBABLY YOU ARE NOW ANXIOUS.
if you connect in your own opinion then problems occur unless
you read this message:
1.
a.let we assume power supply is 5kv-.75amp rating.
b.so, you must connect fuse to that rating.
c.now you decide to connect 600v-.75amp rating fuse.
that means this fuse can't pass over 600*.75=450watts
in your circuits.
d.so to satisfy 450watt rating total current will be(maximum)
( 450watts=5000*i , i(max)=0.09amp).
so load resistance will be r(min)=v/i,r(min)=5000/0.09=55.55k
if you allow less than this load resistance then with equation
p=(v*v)/r, p will exced 450 watts and your fuse will disconnect
from circuit.
conclusion:
So be sure the resistance of load of mininum of 55.55K(ohm).
/**********************/
if you choose less than 55.55k under above circumstances
then it is a good choose to 5kv-.075amp rating fuse.
Thanks you-
by - saifullah
RAJSHAHI , BIT,BANGLADESH
3RD YEAR,SIX SEMESTER.
COMPUTER SCIENCE AND ENGINEERING DEPARTMENT.
B.SC.ENGINEERING.
DATE:09/07/03
email:
[email protected]