need answers
Member
We are winding a real lightweight sheet paper that tears easily. I to am trying to use a footage to stop formula on a control logix processor. We typically run 3000fpm, with a acceleration rate and deceleration rate of 128 ft per sec squared. Our jerk rate is 1 fps cubed. They go into an s curve block that creates the reference to the drive.
We tried the formula that was posted in a older thread X = [V^2 / (2 * a)] + [(V * a) / (2 * J)] , it does not seem to work. From the old thread, we end up in the condition of a^2 > vj as described further into that thread. If I increase J, our paper tears as the drive reacts too quickly.
Does anyone have a good formula that can be used in ladder logic to accomplish this.
Thanks
We tried the formula that was posted in a older thread X = [V^2 / (2 * a)] + [(V * a) / (2 * J)] , it does not seem to work. From the old thread, we end up in the condition of a^2 > vj as described further into that thread. If I increase J, our paper tears as the drive reacts too quickly.
Does anyone have a good formula that can be used in ladder logic to accomplish this.
Thanks